本文实例讲述了Python实现多条件筛选目标数据功能。分享给大家供大家参考,具体如下:
python中提供了一些数据过滤功能,可以使用内建函数,也可以使用循环语句来判断,或者使用pandas库,当然在有些情况下使用pandas是为了提高工作效率。举例如下:
a = [("chic", "JJ"), ("although", "IN"), ("menu", "JJ"), ("items", "NNS"), ("doesnt", "JJ"),
("scream", "NN"), ("french", "JJ"), ("cuisine", "NN")]
这里的a为一个list,列表中还有元组。每一个元组由单词和其词性组成,我们要筛选词性为JJ何NN的单词。可以有三种写法:
第一种,使用内建函数filter:
# -*- coding:utf-8 -*-
#!python3
a = [("chic", "JJ"), ("although", "IN"), ("menu", "JJ"), ("items", "NNS"), ("doesnt", "JJ"),
("scream", "NN"), ("french", "JJ"), ("cuisine", "NN")]
def filt_nn(data_text):
nn_data = filter(lambda x: x[1] == "NN"or x[1] == "JJ", data_text)
# print(list(nn_data))
return list(nn_data)
print(filt_nn(a))
运行结果:
[("chic", "JJ"), ("menu", "JJ"), ("doesnt", "JJ"), ("scream", "NN"), ("french", "JJ"), ("cuisine", "NN")]
第二种,使用pandas包:
# -*- coding:utf-8 -*-
#!python3
import pandas as pd
a = [("chic", "JJ"), ("although", "IN"), ("menu", "JJ"), ("items", "NNS"), ("doesnt", "JJ"),
("scream", "NN"), ("french", "JJ"), ("cuisine", "NN")]
data = pd.DataFrame(a, columns=["word", "ps"])
print(data[data.ps.isin(["JJ", "NN"])].word)
运行结果:
0 chic
2 menu
4 doesnt
5 scream
6 french
7 cuisine
Name: word, dtype: object
第三种,使用循环:
# -*- coding:utf-8 -*-
#!python3
a = [("chic", "JJ"), ("although", "IN"), ("menu", "JJ"), ("items", "NNS"), ("doesnt", "JJ"),
("scream", "NN"), ("french", "JJ"), ("cuisine", "NN")]
absd = []
for i in a:
if i[1] == "NN" or i[1] == "JJ":
absd.append(i[0])
print(absd)
得到的结果都相同,如下:
["chic", "menu", "doesnt", "scream", "french", "cuisine"]
虽然结果相同,但是推荐第一、二种方法,因为这两个方法速度更快。
更多关于Python相关内容可查看本站专题:《Python列表(list)操作技巧总结》、《Python字符串操作技巧汇总》、《Python数据结构与算法教程》、《Python函数使用技巧总结》、《Python入门与进阶经典教程》及《Python文件与目录操作技巧汇总》
希望本文所述对大家Python程序设计有所帮助。
本文标题: Python实现多条件筛选目标数据功能【测试可用】
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