我设法通过jdom(odfdom-java)做到了这一点，毕竟一点都没有使用过。 绑定的xml本身存在于表示odt的xml中。 您只需要知道表单的ID或标签的名称，即可获得正确的节点。 之后，将构造一个字符串，其中包含带有表单数据的xml。 我的代码如下：
import org.apache.xerces.dom.DeepNodeListImpl;
import org.apache.xml.serialize.OutputFormat;
import org.apache.xml.serialize.XMLSerializer;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import java.io.IOException;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
public class TestXFormData {
private static StringBuilder nodeContent;
public static void main(String[] args) throws Exception {
//Unzip the openOffice Document
ZipFile zipFile = new ZipFile("C://myFile.odt");
Enumeration entries = zipFile.entries();
ZipEntry entry;
while(entries.hasMoreElements()) {
entry = (ZipEntry) entries.nextElement();
if (entry.getName().equals("content.xml")) {
// construct document
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder docBuilder = domFactory.newDocumentBuilder();
Document doc = docBuilder.parse(zipFile.getInputStream(entry));
// print the document
printDocument(doc);
// get the node
NodeList list = doc.getElementsByTagName("myTagName");
Node node = ((DeepNodeListImpl) list).item(0);
nodeContent = new StringBuilder();
// print the xml with the form data
prettyPrint(node);
System.out.println(nodeContent.toString());
}
}
}
private static void prettyPrint(Node node) {
if (node.getNodeType() == Node.TEXT_NODE) {
nodeContent.append(node.getNodeValue());
} else if (node.getNodeType() == Node.ELEMENT_NODE) {
nodeContent.append("");
NodeList kids = node.getChildNodes();
for (int i = 0; i < kids.getLength(); i++) {
prettyPrint(kids.item(i));
}
nodeContent.append("" + node.getNodeName() + ">");
}
}
private static void printDocument(Document doc) throws IOException {
OutputFormat format = new OutputFormat(doc);
format.setIndenting(true);
XMLSerializer serializer = new XMLSerializer(System.out, format);
serializer.serialize(doc);
}
}
