js获取多个select下拉框选中的值

js获取多个select下拉框选中的值

var electronicIds = [];

$("select[name='electronicId']").each(function(j,item){

electronicIds.push(document.getElementsByTagName("select")[j].value);

});

例子：

var row= "<div class='table-style'>"

+"<div class='row' id='addRow'>"

+"<div class='col-sm-1 col-xs-4'><span>*</span>电子券：</div>"

+"<div class='col-sm-3 col-xs-8 div-select'>"

+"<select class='form-control dselect' name='electronicId' id='select'>"

+"<option value='' label='' title=''>---请选择---</option>"

+"<#list elist as list>"

+"<option value='${(list.id)!}' label='${(list.typeSign)!}' title='${(list.reduceMoney)!}'>${(list.title)!}</option>"

+"</#list>"

+"</select>"

+"</div>"

+"<div class='col-sm-4 col-xs-12'><button class='btn btn-sm btn-danger ' οnclick='delRow(this)'>删除</button></div>"

+"</div>"

+"</div>";

$("#baseinfo2").append(row);