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PHP5对Mysql5的任意数据库表的管理代码示例(三)

时间:2022-07-09 01:18:33

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PHP5对Mysql5的任意数据库表的管理代码示例(三)

后端开发|php教程

PHP5对Mysql5的任意数据库表的管理代码示例(三)

后端开发-php教程

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续:点击编辑一个条目会跳转至edit.php

//edit.php

Editing an entry from the databaseEdit an entry

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<?

$database = “sunsite”;

$tablename = $_REQUEST[‘tablename’];

echo “Data from $tablename“;

MySQL_connect(“localhost”,”root”,””) or die (“PRoblem connecting to DataBase”);

$query = “show columns from $tablename”;

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

echo “Found these entries in the database:

“;

echo “

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“;

}

else echo “No data.”;

mysql_free_result($result);

?>

“>Finish

然后选择其中一个id,会跳出具体的内容并要求用户修改。

//editing.php

Editing an entry

Editing an entry

<?

$database = “sunsite”;

$tablename = $_GET[‘tablename’];

mysql_connect(“localhost”,”root”,””) or die (“Problem connecting to DataBase”);

$query = “show columns from $tablename”;

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

while ($r = mysql_fetch_array($result))

{

$colname[$column] = $r[0];

$column = $column + 1;

}

mysql_free_result($result);

}

$temp = $_GET[$colname[0]];

$query = “select * from $tablename where $colname[0]=$temp”;

$result = mysql_db_query($database,$query);

$r = mysql_fetch_array($result);

?>

最后是写入数据库

//editdb.php

<?

$database = “sunsite”;

$tablename = $_POST[‘tablename’];

mysql_connect(“localhost”,”root”,””) or die (“Problem connecting to DataBase”);

$query = “show columns from $tablename”;

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

while ($r = mysql_fetch_array($result))

{

$colname[$column] = $r[0];

$column = $column + 1;

}

mysql_free_result($result);

}

for($col=0;$col<$column;$col++)

$para[$col] = $_POST[$colname[$col]];

if ($_POST[‘name’])

{

mysql_connect(“localhost”,”root”,””) or die (“Problem connecting to DataBase”);

$query = “update $tablename set $colname[1]=’$para[1]”;

for($col=2;$col<$column;$col++)

$query = $query . “,$colname[$col]=’$para[$col]”;

$query = $query . ” where $colname[0]=’$para[0]’;”;

$result = mysql_db_query($database, $query);

Header(“Location: edit.php?tablename=$tablename”);

}

else

{

echo “No name Entered. Please go back and reenter name”;

}

?>

待续。

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